What is the answer to log_{a}(x)=log_{2}(1) ?

The answer to log_{a}(x)=log_{2}(1) is x=1 {0 1}

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log_{a}(x)=log_{2}(1)

lo g_{a} (x) = lo g_{2} (1)

x = 1 {0 < a < 1 or a > 1}

Solution steps

lo g_{a} (x) = lo g_{2} (1)

Apply log rules

x = 1

Verify Solutions:

x = 1 {0 < a < 1 or a > 1}

The solution is

x = 1 {0 < a < 1 or a > 1}

lo g_{3}^{2} (x) - 2 lo g_{3} (x) = 0

x, lo g_{b} (x) = y

lo g_{3} (x) + lo g_{3} (a) = 0

ln (r) = 6

x, lo g_{b} (x) = a

What is the answer to log_{a}(x)=log_{2}(1) ?
The answer to log_{a}(x)=log_{2}(1) is x=1 {0<a<1\lor a>1}