What is the answer to solvefor p,ln(p)-ln(-p+1)=t ?

The answer to solvefor p,ln(p)-ln(-p+1)=t is p=(e^t)/(1+e^t)

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solvefor p,ln(p)-ln(-p+1)=t

solve for

p, ln (p) - ln (- p + 1) = t

p = \frac{e ^{t}}{1 + e ^{t}}

Solution steps

ln (p) - ln (- p + 1) = t

Add

ln (- p + 1)

to both sides

ln (p) - ln (- p + 1) + ln (- p + 1) = t + ln (- p + 1)

Simplify

ln (p) = t + ln (- p + 1)

Apply log rules

p = e^{t} (- p + 1)

Solve

p = e^{t} (- p + 1) : p = \frac{e ^{t}}{1 + e ^{t}}

p = \frac{e ^{t}}{1 + e ^{t}}

Verify Solutions:

p = \frac{e ^{t}}{1 + e ^{t}}

True

The solution is

p = \frac{e ^{t}}{1 + e ^{t}}

3 lo g_{a^{3}} (x) = lo g_{a} (x)

3.547 = lo g_{10} (x)

2 - 6 ln (3 x) = 10

20 \cdot lo g_{10} (2 x) = 13.7

lo g_{8} (x) = \frac{- 1}{3}

What is the answer to solvefor p,ln(p)-ln(-p+1)=t ?
The answer to solvefor p,ln(p)-ln(-p+1)=t is p=(e^t)/(1+e^t)