What is the answer to log_{2}(x-4)+log_{2}(x)=5 ?

The answer to log_{2}(x-4)+log_{2}(x)=5 is x=8

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log_{2}(x-4)+log_{2}(x)=5

lo g_{2} (x - 4) + lo g_{2} (x) = 5

x = 8

Solution steps

lo g_{2} (x - 4) + lo g_{2} (x) = 5

Apply log rules

(x - 4) x = 32

Solve

(x - 4) x = 32 : x = 8, x = - 4

x = 8, x = - 4

Verify Solutions:

x = 8

True

, x = - 4

False

The solution is

x = 8

lo g_{2} (16) = lo g_{4} (x)

8 = 5 - 4 ln (3 t - 4)

lo g_{3} (x) = 1 + lo g_{3} (20)

ln (- x) = - 2

lo g_{x} (4) = 0.5

What is the answer to log_{2}(x-4)+log_{2}(x)=5 ?
The answer to log_{2}(x-4)+log_{2}(x)=5 is x=8
Solve for x: log_{2}(x-4)+log_{2}(x)=5
The solution is x=8