What is the answer to solvefor x,ln(x)=4ln(t)+c ?

The answer to solvefor x,ln(x)=4ln(t)+c is x=e^ct^4

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solvefor x,ln(x)=4ln(t)+c

solve for

x, ln (x) = 4 ln (t) + c

x = e^{c} t^{4}

Solution steps

ln (x) = 4 ln (t) + c

Apply log rules

x = e^{c} t^{4}

lo g_{3} (x) - 2 = lo g_{3} (x - 8)

x \frac{1}{2} ln (x - 1) = 0

lo g_{2} (x^{2} - 8 x - 16) = 2

lo g_{2} (x + 1) = lo g_{3} (34.67)

lo g_{3} (2 x + 1) - lo g_{3} (x - 2) = 1

What is the answer to solvefor x,ln(x)=4ln(t)+c ?
The answer to solvefor x,ln(x)=4ln(t)+c is x=e^ct^4