What is the answer to log_{2}(2x)+2log_{2}(8)=2 ?

The answer to log_{2}(2x)+2log_{2}(8)=2 is x= 1/32

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log_{2}(2x)+2log_{2}(8)=2

lo g_{2} (2 x) + 2 lo g_{2} (8) = 2

x = \frac{1}{32}

Decimal Notation

x = 0.03125

Solution steps

lo g_{2} (2 x) + 2 lo g_{2} (8) = 2

Move

2 lo g_{2} (8)

to the right side

lo g_{2} (2 x) = 2 - 2 lo g_{2} (8)

Apply log rules

2 x = \frac{1}{16}

Solve

2 x = \frac{1}{16} : x = \frac{1}{32}

x = \frac{1}{32}

Verify Solutions:

x = \frac{1}{32}

True

The solution is

x = \frac{1}{32}

4 ln (4 x) = 20

x, ln (1 - x) = - k t

lo g_{3} (x) = - \frac{1}{3}

lo g_{2} (3 x + 2) = 3

lo g_{2} (x + 3) = - 2

What is the answer to log_{2}(2x)+2log_{2}(8)=2 ?
The answer to log_{2}(2x)+2log_{2}(8)=2 is x= 1/32
Solve for x: log_{2}(2x)+2log_{2}(8)=2
The solution is x= 1/32