What is the answer to ln(x)+ln(5x)=-3 ?

The answer to ln(x)+ln(5x)=-3 is x=e^{(-3-ln(5))/2}

Solve for x: ln(x)+ln(5x)=-3

The solution is x=e^{(-3-ln(5))/2}

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ln (x) + ln (5 x) = - 3

x = e^{\frac{- 3 - l n ( 5 )}{2}}

Decimal

x = 0.09978 \dots

Solution steps

ln (x) + ln (5 x) = - 3

Apply log rules

x = e^{\frac{- 3 - l n ( 5 )}{2}}

Verify Solutions:

x = e^{\frac{- 3 - l n ( 5 )}{2}}

True

The solution is

x = e^{\frac{- 3 - l n ( 5 )}{2}}

ln (x) = \frac{2 - ln ( x )}{ln ( x )}

lo g_{3} (x) = - lo g_{3} (2) + 2

y, ln (y) = 0.85 x + c

ln (x) = 2.0353

50 = 12.036 ln (x) + 2.9211

What is the answer to ln(x)+ln(5x)=-3 ?
The answer to ln(x)+ln(5x)=-3 is x=e^{(-3-ln(5))/2}
Solve for x: ln(x)+ln(5x)=-3
The solution is x=e^{(-3-ln(5))/2}