What is the answer to log_{7}(x+5)+log_{7}(x-1)=1 ?

The answer to log_{7}(x+5)+log_{7}(x-1)=1 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{7}(x+5)+log_{7}(x-1)=1

lo g_{7} (x + 5) + lo g_{7} (x - 1) = 1

x = 2

Solution steps

lo g_{7} (x + 5) + lo g_{7} (x - 1) = 1

Apply log rules

(x + 5) (x - 1) = 7

Solve

(x + 5) (x - 1) = 7 : x = 2, x = - 6

x = 2, x = - 6

Verify Solutions:

x = 2

True

, x = - 6

False

The solution is

x = 2

lo g_{16} (N) = \frac{1}{4}

4 lo g_{10} (x + 6) = 0

50 = - 20 lo g_{10} (r)

ln (4 x - 3) = 5

ln (4 x - 3) = 3

What is the answer to log_{7}(x+5)+log_{7}(x-1)=1 ?
The answer to log_{7}(x+5)+log_{7}(x-1)=1 is x=2
Solve for x: log_{7}(x+5)+log_{7}(x-1)=1
The solution is x=2