What is the answer to ln(x)+ln(5-2x)=0 ?

The answer to ln(x)+ln(5-2x)=0 is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4

Solve for x: ln(x)+ln(5-2x)=0

The solution is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4

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ln (x) + ln (5 - 2 x) = 0

x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

Decimal Notation

x = 0.21922 \dots, x = 2.28077 \dots

Solution steps

ln (x) + ln (5 - 2 x) = 0

Apply log rules

x (5 - 2 x) = 1

Solve

x (5 - 2 x) = 1 : x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

Verify Solutions:

x = \frac{5 - 17}{4}

True

, x = \frac{5 + 17}{4}

True

The solutions are

x = \frac{5 - 17}{4}, x = \frac{5 + 17}{4}

lo g_{6561} (N) = - \frac{3}{4}

lo g_{2} (x) - lo g_{2} (x - 2) = 4

x, ln (x) = a + b (ln (y))

\frac{1}{2} ln (4 + c) = 0

lo g_{2} (z) = 6.754

What is the answer to ln(x)+ln(5-2x)=0 ?
The answer to ln(x)+ln(5-2x)=0 is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4
Solve for x: ln(x)+ln(5-2x)=0
The solution is x=(5-sqrt(17))/4 ,x=(5+sqrt(17))/4