What is the answer to ln(5)-ln(4-4x)=ln(33) ?

The answer to ln(5)-ln(4-4x)=ln(33) is x= 127/132

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ln(5)-ln(4-4x)=ln(33)

ln (5) - ln (4 - 4 x) = ln (33)

x = \frac{127}{132}

Decimal Notation

x = 0.96212 \dots

Solution steps

ln (5) - ln (4 - 4 x) = ln (33)

Move

ln (5)

to the right side

- ln (4 - 4 x) = ln (33) - ln (5)

Divide both sides by

- 1

ln (4 - 4 x) = - ln (33) + ln (5)

Apply log rules

4 - 4 x = \frac{5}{33}

Solve

4 - 4 x = \frac{5}{33} : x = \frac{127}{132}

x = \frac{127}{132}

Verify Solutions:

x = \frac{127}{132}

True

The solution is

x = \frac{127}{132}

\frac{ln ( x )}{x} x = 1

lo g_{2} (x - 10) = 5

63 = 95 - 93 lo g_{10} (t + 1)

lo g_{a} (64) = 6

lo g_{3 + x} (x^{2} - x) = 1

What is the answer to ln(5)-ln(4-4x)=ln(33) ?
The answer to ln(5)-ln(4-4x)=ln(33) is x= 127/132
Solve for x: ln(5)-ln(4-4x)=ln(33)
The solution is x= 127/132