What is factor x^3-7x^2+2x+40 ?

The solution to factor x^3-7x^2+2x+40 is (x+2)(x-4)(x-5)

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factor x^3-7x^2+2x+40

factor

x^{3} - 7 x^{2} + 2 x + 40

(x + 2) (x - 4) (x - 5)

Solution steps

x^{3} - 7 x^{2} + 2 x + 40

Use the rational root theorem

= (x + 2) \frac{x ^{3} - 7 x ^{2} + 2 x + 40}{x + 2}

\frac{x ^{3} - 7 x ^{2} + 2 x + 40}{x + 2} = x^{2} - 9 x + 20

= (x + 2) (x^{2} - 9 x + 20)

Factor

x^{2} - 9 x + 20 : (x - 4) (x - 5)

= (x + 2) (x - 4) (x - 5)

4 = 2 + y

\frac{3}{2} + \frac{2}{3}

(x^{2} y^{3} + \frac{x ^{2} ( x + y )}{x - y} + y^{5})^{6}

\frac{4 m - 7}{2} = 18

6 t^{2} - 102 t

What is factor x^3-7x^2+2x+40 ?
The solution to factor x^3-7x^2+2x+40 is (x+2)(x-4)(x-5)