What is the answer to solvefor a,h=k+log_{10}(ac) ?

The answer to solvefor a,h=k+log_{10}(ac) is a=(10^{h-k})/c

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solvefor a,h=k+log_{10}(ac)

solve for

a, h = k + lo g_{10} (a c)

a = \frac{1 0 ^{h - k}}{c}

Solution steps

h = k + lo g_{10} (a c)

Switch sides

k + lo g_{10} (a c) = h

Move

k

to the right side

lo g_{10} (a c) = h - k

Apply log rules

a c = 1 0^{h - k}

Solve

a c = 1 0^{h - k} : a = \frac{1 0 ^{h - k}}{c}

a = \frac{1 0 ^{h - k}}{c}

ln (x) = 19.21

9.6 = - lo g_{10} (x)

ln (x) = - 1.59

lo g_{10} (x + 2) = 2 - lo g_{10} (x)

lo g_{3} (x) + 3 lo g_{x} (3) = 4

What is the answer to solvefor a,h=k+log_{10}(ac) ?
The answer to solvefor a,h=k+log_{10}(ac) is a=(10^{h-k})/c