What is the answer to solvefor m,11=klog_{10}(m+5) ?

The answer to solvefor m,11=klog_{10}(m+5) is m=10^{(11)/k}-5 {k 0}

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solvefor m,11=klog_{10}(m+5)

solve for

m, 11 = k lo g_{10} (m + 5)

m = 1 0^{\frac{11}{k}} - 5 {k < 0 or k > 0}

Solution steps

11 = k lo g_{10} (m + 5)

Switch sides

k lo g_{10} (m + 5) = 11

Divide both sides by

k

lo g_{10} (m + 5) = \frac{11}{k}

Apply log rules

m + 5 = 1 0^{\frac{11}{k}}

Solve

m + 5 = 1 0^{\frac{11}{k}} : m = 1 0^{\frac{11}{k}} - 5

m = 1 0^{\frac{11}{k}} - 5

Verify Solutions:

m = 1 0^{\frac{11}{k}} - 5 {k < 0 or k > 0}

The solution is

m = 1 0^{\frac{11}{k}} - 5 {k < 0 or k > 0}

ln (x + 7.5) + ln (2) = 2 ln (x)

3^{l o g_{10} (x) 81} = x

ln (x) = - 1.31

3 lo g_{3} (3 x) = 1

lo g_{2} (x) - lo g_{2} (x + 3) = 1

What is the answer to solvefor m,11=klog_{10}(m+5) ?
The answer to solvefor m,11=klog_{10}(m+5) is m=10^{(11)/k}-5 {k<0\lor k>0}