What is the answer to ln(2x+3)+ln(3x)=2 ?

The answer to ln(2x+3)+ln(3x)=2 is x=(-9+sqrt(81+24e^2))/(12)

Solve for x: ln(2x+3)+ln(3x)=2

The solution is x=(-9+sqrt(81+24e^2))/(12)

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ln (2 x + 3) + ln (3 x) = 2

x = \frac{- 9 + 81 + 24 e ^{2}}{12}

Decimal Notation

x = 0.58940 \dots

Solution steps

ln (2 x + 3) + ln (3 x) = 2

Apply log rules

(2 x + 3) \cdot 3 x = e^{2}

Solve

(2 x + 3) \cdot 3 x = e^{2} : x = \frac{- 9 + 81 + 24 e ^{2}}{12}, x = \frac{- 9 - 81 + 24 e ^{2}}{12}

x = \frac{- 9 + 81 + 24 e ^{2}}{12}, x = \frac{- 9 - 81 + 24 e ^{2}}{12}

Verify Solutions:

x = \frac{- 9 + 81 + 24 e ^{2}}{12}

True

, x = \frac{- 9 - 81 + 24 e ^{2}}{12}

False

The solution is

x = \frac{- 9 + 81 + 24 e ^{2}}{12}

lo g_{4} (3 x + 4) + lo g_{4} (16) = 1

y, ln (y) = 2 t

ln (lo g_{10} (x^{2} + 1)) = 0

0 = 2 ln (x + 1)

x, ln (6 - x) = 0.6

What is the answer to ln(2x+3)+ln(3x)=2 ?
The answer to ln(2x+3)+ln(3x)=2 is x=(-9+sqrt(81+24e^2))/(12)
Solve for x: ln(2x+3)+ln(3x)=2
The solution is x=(-9+sqrt(81+24e^2))/(12)