What is the answer to y=ln(y)-1 ?

The answer to y=ln(y)-1 is No Solution for y\in\mathbb{R}

Solve for y: y=ln(y)-1

The solution is No Solution for y\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y = ln (y) - 1

No Solution for y \in R

Solution steps

y = ln (y) - 1

Switch sides

ln (y) - 1 = y

Move

1

to the right side

ln (y) = y + 1

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (y)} = e^{y + 1}

Simplify

e^{l n (y)} : y

y = e^{y + 1}

Solve

y = e^{y + 1} :

No Solution for

y \in R

No Solution for y \in R

lo g_{5} (5 x - 1) = lo g_{5} (4 x + 5)

lo g_{3} (lo g_{3} (x + 5)) = 1

12 = ln (\frac{900}{900 - x})

lo g_{10} (x) \cdot 20 = - 80

ln (v) = 3.39 - 0.0785 k

What is the answer to y=ln(y)-1 ?
The answer to y=ln(y)-1 is No Solution for y\in\mathbb{R}
Solve for y: y=ln(y)-1
The solution is No Solution for y\in\mathbb{R}