What is the answer to 32=(50)/(ln(q+1)) ?

The answer to 32=(50)/(ln(q+1)) is q=e^{25/16}-1

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32=(50)/(ln(q+1))

32 = \frac{50}{ln ( q + 1 )}

q = e^{\frac{25}{16}} - 1

Decimal Notation

q = 3.77073 \dots

Solution steps

32 = \frac{50}{ln ( q + 1 )}

Rewrite the equation with

ln (q + 1) = u

32 = \frac{50}{u}

Solve

32 = \frac{50}{u} : u = \frac{25}{16}

u = \frac{25}{16}

Substitute back

u = ln (q + 1),

solve for

q

Solve

ln (q + 1) = \frac{25}{16} : q = e^{\frac{25}{16}} - 1

q = e^{\frac{25}{16}} - 1

Verify Solutions:

q = e^{\frac{25}{16}} - 1

True

The solution is

q = e^{\frac{25}{16}} - 1

ln (7 x) = 1

lo g_{10} (3 - 2 x) = 1

ln (x) - ln (5) = 0

ln (1) = ln (- 7 t)

y, ln (y) = 9 t + 7

What is the answer to 32=(50)/(ln(q+1)) ?
The answer to 32=(50)/(ln(q+1)) is q=e^{25/16}-1
Solve for q: 32=(50)/(ln(q+1))
The solution is q=e^{25/16}-1