What is the answer to ln(4k-7)=2,k ?

The answer to ln(4k-7)=2,k is k=(e^2+7)/4

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ln(4k-7)=2,k

ln (4 k - 7) = 2, k

k = \frac{e ^{2} + 7}{4}

Decimal Notation

k = 3.59726 \dots

Solution steps

ln (4 k - 7) = 2

Apply log rules

4 k - 7 = e^{2}

Solve

4 k - 7 = e^{2} : k = \frac{e ^{2} + 7}{4}

k = \frac{e ^{2} + 7}{4}

ln (2) = ln (- \frac{1}{1} + c)

lo g_{7} (x) = 216

5 x - 7 ln (x) = π

ln (1 + x) = 1 + ln (x)

ln (x) = 1