What is the answer to log_{4}(3x)-1=log_{4}(-2x+9) ?

The answer to log_{4}(3x)-1=log_{4}(-2x+9) is x= 36/11

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log_{4}(3x)-1=log_{4}(-2x+9)

lo g_{4} (3 x) - 1 = lo g_{4} (- 2 x + 9)

x = \frac{36}{11}

Decimal Notation

x = 3.27272 \dots

Solution steps

lo g_{4} (3 x) - 1 = lo g_{4} (- 2 x + 9)

Apply log rules

3 x = (- 2 x + 9) \cdot 4

Solve

3 x = (- 2 x + 9) \cdot 4 : x = \frac{36}{11}

x = \frac{36}{11}

Verify Solutions:

x = \frac{36}{11}

True

The solution is

x = \frac{36}{11}

ln (7 x + e) = - 6

2 ln (x) = ln (2) - 3 ln (2)

lo g_{2} (\frac{5}{x}) = 3

lo g_{4} (x + 1) - lo g_{4} (7 - 2 x) = 0

lo g_{b} (x) + 2 = lo g_{b} (x + 2)

What is the answer to log_{4}(3x)-1=log_{4}(-2x+9) ?
The answer to log_{4}(3x)-1=log_{4}(-2x+9) is x= 36/11
Solve for x: log_{4}(3x)-1=log_{4}(-2x+9)
The solution is x= 36/11