What is the answer to log_{2}(2x-1)+4=log_{2}(x) ?

The answer to log_{2}(2x-1)+4=log_{2}(x) is x= 16/31

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log_{2}(2x-1)+4=log_{2}(x)

lo g_{2} (2 x - 1) + 4 = lo g_{2} (x)

x = \frac{16}{31}

Decimal Notation

x = 0.51612 \dots

Solution steps

lo g_{2} (2 x - 1) + 4 = lo g_{2} (x)

Apply log rules

(2 x - 1) \cdot 16 = x

Solve

(2 x - 1) \cdot 16 = x : x = \frac{16}{31}

x = \frac{16}{31}

Verify Solutions:

x = \frac{16}{31}

True

The solution is

x = \frac{16}{31}

lo g_{10} (3 x + 3) = 3

5 ln (2 x + 5) - 14 = 1616

x, lo g_{x} (36) = 1.842

lo g_{10} (x) = 4.4 + 1.5 (2.8)

6.8 = - lo g_{10} (x)

What is the answer to log_{2}(2x-1)+4=log_{2}(x) ?
The answer to log_{2}(2x-1)+4=log_{2}(x) is x= 16/31
Solve for x: log_{2}(2x-1)+4=log_{2}(x)
The solution is x= 16/31