What is the answer to n=ln^2(x) ?

The answer to n=ln^2(x) is x=e^{sqrt(n)} {No Solution},x=e^{-sqrt(n)}

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n=ln^2(x)

n = ln^{2} (x)

x = e^{n} {No Solution}, x = e^{- n}

Solution steps

n = ln^{2} (x)

Rewrite the equation with

ln (x) = u

n = u^{2}

Solve

n = u^{2} : u = n, u = - n

u = n, u = - n

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = n : x = e^{n}

Solve

ln (x) = - n : x = e^{- n}

x = e^{n}, x = e^{- n}

Verify Solutions:

x = e^{n} {No Solution}, x = e^{- n}

True

The solutions are

x = e^{n} {No Solution}, x = e^{- n}

lo g_{8} (X) = \frac{1}{3}

5 ln (6 x - 2) + 13 = 23

lo g_{x} (25) = lo g_{5} (125) - 1

127 = lo g_{2} (x)

12.828 = 10 \cdot ln (2 + z)

What is the answer to n=ln^2(x) ?
The answer to n=ln^2(x) is x=e^{sqrt(n)} {No Solution},x=e^{-sqrt(n)}