What is the answer to ln(2t+1)= 9/4 ?

The answer to ln(2t+1)= 9/4 is t=(e^{9/4}-1)/2

Solve for t: ln(2t+1)= 9/4

The solution is t=(e^{9/4}-1)/2

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ln (2 t + 1) = \frac{9}{4}

t = \frac{e ^{\frac{9}{4}} - 1}{2}

Decimal Notation

t = 4.24386 \dots

Solution steps

ln (2 t + 1) = \frac{9}{4}

Apply log rules

2 t + 1 = e^{\frac{9}{4}}

Solve

2 t + 1 = e^{\frac{9}{4}} : t = \frac{e ^{\frac{9}{4}} - 1}{2}

t = \frac{e ^{\frac{9}{4}} - 1}{2}

a, ln (a) + ln (b) = c

0 = 2 ln (x) + 2

10 lo g_{10} (R) = 340227

lo g_{2} (x + 10) - 3 = 0

3 = a + b lo g_{e} (x)

What is the answer to ln(2t+1)= 9/4 ?
The answer to ln(2t+1)= 9/4 is t=(e^{9/4}-1)/2
Solve for t: ln(2t+1)= 9/4
The solution is t=(e^{9/4}-1)/2