What is the answer to log_{2}(6x+5)=1 ?

The answer to log_{2}(6x+5)=1 is x=-1/2

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log_{2}(6x+5)=1

lo g_{2} (6 x + 5) = 1

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

lo g_{2} (6 x + 5) = 1

Apply log rules

6 x + 5 = 2

Solve

6 x + 5 = 2 : x = - \frac{1}{2}

x = - \frac{1}{2}

y, x = lo g_{2} (y - 4)

lo g_{2} (6 x + 5) = 2

0 = lo g_{3} (x - 1) - 2

A, ln (A) = c + k \cdot t

lo g_{7} (x) = 1.8