What are the solutions to the equation x^2-14x+50=0 ?

The solutions to the equation x^2-14x+50=0 are x=7+i,x=7-i

Find the zeros of x^2-14x+50=0

The zeros of x^2-14x+50=0 are x=7+i,x=7-i

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x^{2} - 14 x + 50 = 0

x = 7 + i, x = 7 - i

Solution steps

x^{2} - 14 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 50 : 2 i

x_{1, 2} = \frac{- ( - 14 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 i}{2 \cdot 1} : 7 + i

x = \frac{- ( - 14 ) - 2 i}{2 \cdot 1} : 7 - i

The solutions to the quadratic equation are:

x = 7 + i, x = 7 - i

(2 - x)^{2} (x - \frac{9}{2}) < 0

\frac{7}{3}

∣ 4 - 3 x ∣ \geq 8

\frac{1}{x + y i}

y^{3} - y^{2} + y - 1

What are the solutions to the equation x^2-14x+50=0 ?
The solutions to the equation x^2-14x+50=0 are x=7+i,x=7-i
Find the zeros of x^2-14x+50=0
The zeros of x^2-14x+50=0 are x=7+i,x=7-i