What is the answer to log_{3}(x+4)+log_{3}(x+1)=2 ?

The answer to log_{3}(x+4)+log_{3}(x+1)=2 is x=(-5+3sqrt(5))/2

Solve for x: log_{3}(x+4)+log_{3}(x+1)=2

The solution is x=(-5+3sqrt(5))/2

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lo g_{3} (x + 4) + lo g_{3} (x + 1) = 2

x = \frac{- 5 + 3 5}{2}

Decimal Notation

x = 0.85410 \dots

Solution steps

lo g_{3} (x + 4) + lo g_{3} (x + 1) = 2

Apply log rules

(x + 4) (x + 1) = 9

Solve

(x + 4) (x + 1) = 9 : x = \frac{- 5 + 3 5}{2}, x = \frac{- 5 - 3 5}{2}

x = \frac{- 5 + 3 5}{2}, x = \frac{- 5 - 3 5}{2}

Verify Solutions:

x = \frac{- 5 + 3 5}{2}

True

, x = \frac{- 5 - 3 5}{2}

False

The solution is

x = \frac{- 5 + 3 5}{2}

1.5 = - lo g_{10} (T)

lo g_{10} (x) = 8.935, x

lo g_{2} (x + 1) = lo g_{3} (2 7^{2})

lo g_{x} (42) = 10

\frac{9}{2} lo g_{5} (x) = - 8

What is the answer to log_{3}(x+4)+log_{3}(x+1)=2 ?
The answer to log_{3}(x+4)+log_{3}(x+1)=2 is x=(-5+3sqrt(5))/2
Solve for x: log_{3}(x+4)+log_{3}(x+1)=2
The solution is x=(-5+3sqrt(5))/2