What is the answer to log_{4}(x)+5log_{2}(x)-36=0 ?

The answer to log_{4}(x)+5log_{2}(x)-36=0 is x=64*4^{3/11}

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log_{4}(x)+5log_{2}(x)-36=0

lo g_{4} (x) + 5 lo g_{2} (x) - 36 = 0

x = 64 \cdot 4^{\frac{3}{11}}

Decimal Notation

x = 93.40672 \dots

Solution steps

lo g_{4} (x) + 5 lo g_{2} (x) - 36 = 0

Apply log rules

x = 64 \cdot 4^{\frac{3}{11}}

Verify Solutions:

x = 64 \cdot 4^{\frac{3}{11}}

True

The solution is

x = 64 \cdot 4^{\frac{3}{11}}

lo g_{10} (d) = 3.7 - 0.2 \cdot 20

lo g_{x} (3 x^{2} - 13 x + 15) = 2

- 2 ln (5 x) = ln (9) - ln (5)

lo g_{x} (\frac{1}{64}) = 2

lo g_{10} (x) = - 4138

What is the answer to log_{4}(x)+5log_{2}(x)-36=0 ?
The answer to log_{4}(x)+5log_{2}(x)-36=0 is x=64*4^{3/11}
Solve for x: log_{4}(x)+5log_{2}(x)-36=0
The solution is x=64*4^{3/11}