What is the answer to log_{5}(3x+1)+log_{5}(x-3)=3 ?

The answer to log_{5}(3x+1)+log_{5}(x-3)=3 is x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{5}(3x+1)+log_{5}(x-3)=3

lo g_{5} (3 x + 1) + lo g_{5} (x - 3) = 3

x = 8

Solution steps

lo g_{5} (3 x + 1) + lo g_{5} (x - 3) = 3

Apply log rules

(3 x + 1) (x - 3) = 125

Solve

(3 x + 1) (x - 3) = 125 : x = 8, x = - \frac{16}{3}

x = 8, x = - \frac{16}{3}

Verify Solutions:

x = 8

True

, x = - \frac{16}{3}

False

The solution is

x = 8

lo g_{\frac{1}{2}} (5 x - 5) = 3

ln (x) = - 1.2494

lo g_{10} (x + 40) = 2

lo g_{x} (7) = \frac{1}{2}

u, ln (u) - ln (1 - u) = t + C

What is the answer to log_{5}(3x+1)+log_{5}(x-3)=3 ?
The answer to log_{5}(3x+1)+log_{5}(x-3)=3 is x=8
Solve for x: log_{5}(3x+1)+log_{5}(x-3)=3
The solution is x=8