What is the answer to 5-ln(x^2-25)=0 ?

The answer to 5-ln(x^2-25)=0 is x=sqrt(e^5+25),x=-sqrt(e^5+25)

Solve for x: 5-ln(x^2-25)=0

The solution is x=sqrt(e^5+25),x=-sqrt(e^5+25)

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5 - ln (x^{2} - 25) = 0

x = e^{5} + 25, x = - e^{5} + 25

Decimal Notation

x = 13.16864 \dots, x = - 13.16864 \dots

Solution steps

5 - ln (x^{2} - 25) = 0

Move

5

to the right side

- ln (x^{2} - 25) = - 5

Divide both sides by

- 1

ln (x^{2} - 25) = 5

Apply log rules

x^{2} - 25 = e^{5}

Solve

x^{2} - 25 = e^{5} : x = e^{5} + 25, x = - e^{5} + 25

x = e^{5} + 25, x = - e^{5} + 25

Verify Solutions:

x = e^{5} + 25

True

, x = - e^{5} + 25

True

The solutions are

x = e^{5} + 25, x = - e^{5} + 25

lo g_{4} (x - 1) = lo g_{2} (x - 1)

lo g_{2} (y^{3} + 3) = 7

(ln (x) - ln (9 - x)) = 9 ab + ln (c)

lo g_{x - 3} (x) = \frac{9}{5}

n \cdot lo g_{10} (n) = n

What is the answer to 5-ln(x^2-25)=0 ?
The answer to 5-ln(x^2-25)=0 is x=sqrt(e^5+25),x=-sqrt(e^5+25)
Solve for x: 5-ln(x^2-25)=0
The solution is x=sqrt(e^5+25),x=-sqrt(e^5+25)