What is the answer to log_{2}(x)+log_{2}(x+2)=2 ?

The answer to log_{2}(x)+log_{2}(x+2)=2 is x=-1+sqrt(5)

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log_{2}(x)+log_{2}(x+2)=2

lo g_{2} (x) + lo g_{2} (x + 2) = 2

x = - 1 + 5

Decimal Notation

x = 1.23606 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (x + 2) = 2

Apply log rules

x (x + 2) = 4

Solve

x (x + 2) = 4 : x = - 1 + 5, x = - 1 - 5

x = - 1 + 5, x = - 1 - 5

Verify Solutions:

x = - 1 + 5

True

, x = - 1 - 5

False

The solution is

x = - 1 + 5

ln (10 x + 5) - 3 = ln (x - 5)

7 lo g_{2} (x) = - \frac{7}{3}

x, 2 - 2.12 = lo g_{10} (x)

lo g_{7} (x + 4) = 0

lo g_{12} (10) = lo g_{12} (6 - p)

What is the answer to log_{2}(x)+log_{2}(x+2)=2 ?
The answer to log_{2}(x)+log_{2}(x+2)=2 is x=-1+sqrt(5)
Solve for x: log_{2}(x)+log_{2}(x+2)=2
The solution is x=-1+sqrt(5)