What is the answer to solvefor x,1+log_{2}(-5x)=4 ?

The answer to solvefor x,1+log_{2}(-5x)=4 is x=-8/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,1+log_{2}(-5x)=4

solve for

x, 1 + lo g_{2} (- 5 x) = 4

x = - \frac{8}{5}

Decimal Notation

x = - 1.6

Solution steps

1 + lo g_{2} (- 5 x) = 4

Move

1

to the right side

lo g_{2} (- 5 x) = 3

Apply log rules

- 5 x = 8

Solve

- 5 x = 8 : x = - \frac{8}{5}

x = - \frac{8}{5}

Verify Solutions:

x = - \frac{8}{5}

True

The solution is

x = - \frac{8}{5}

x, lo g_{2} (6 x + 4) = 1

lo g_{y} (25) = 2

ln (x) + ln (7 x) = 4

- ln (3 - x) = ln (2 + x)

lo g_{5} (x^{2} - 11 x + 49) = 2

What is the answer to solvefor x,1+log_{2}(-5x)=4 ?
The answer to solvefor x,1+log_{2}(-5x)=4 is x=-8/5