What are the solutions to the equation 3x^2+18x=0 ?

The solutions to the equation 3x^2+18x=0 are x=0,x=-6

Find the zeros of 3x^2+18x=0

The zeros of 3x^2+18x=0 are x=0,x=-6

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3 x^{2} + 18 x = 0

x = 0, x = - 6

Solution steps

3 x^{2} + 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 0 = 18

x_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 18}{2 \cdot 3}, x_{2} = \frac{- 18 - 18}{2 \cdot 3}

x = \frac{- 18 + 18}{2 \cdot 3} : 0

x = \frac{- 18 - 18}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

(\frac{2 a ^{6} \cdot 2 a ^{5} b ^{4}}{2 a ^{3}})^{3}

5 (7 - x) + 2 x < 6 x - 2 - 9 x

3 x - 27

3 x - 7 = 2 x - 2

0.85 = \frac{3425.1 - x}{3425.1 - 2006.958}

What are the solutions to the equation 3x^2+18x=0 ?
The solutions to the equation 3x^2+18x=0 are x=0,x=-6
Find the zeros of 3x^2+18x=0
The zeros of 3x^2+18x=0 are x=0,x=-6