What is the answer to log_{4}(x-9)log_{4}(x-9)=7 ?

The answer to log_{4}(x-9)log_{4}(x-9)=7 is x=4^{sqrt(7)}+9,x= 1/(4^{sqrt(7))}+9

Solve for x: log_{4}(x-9)log_{4}(x-9)=7

The solution is x=4^{sqrt(7)}+9,x= 1/(4^{sqrt(7))}+9

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lo g_{4} (x - 9) lo g_{4} (x - 9) = 7

x = 4^{7} + 9, x = \frac{1}{4 ^{7}} + 9

Decimal Notation

x = 48.16525 \dots, x = 9.02553 \dots

Solution steps

lo g_{4} (x - 9) lo g_{4} (x - 9) = 7

Rewrite the equation with

lo g_{4} (x - 9) = u

uu = 7

Solve

uu = 7 : u = 7, u = - 7

u = 7, u = - 7

Substitute back

u = lo g_{4} (x - 9),

solve for

x

Solve

lo g_{4} (x - 9) = 7 : x = 4^{7} + 9

Solve

lo g_{4} (x - 9) = - 7 : x = \frac{1}{4 ^{7}} + 9

x = 4^{7} + 9, x = \frac{1}{4 ^{7}} + 9

Verify Solutions:

x = 4^{7} + 9

True

, x = \frac{1}{4 ^{7}} + 9

True

The solutions are

x = 4^{7} + 9, x = \frac{1}{4 ^{7}} + 9

3 + 3 \cdot ln (5) = 3 \cdot ln (x)

lo g_{5} (a + 1) = 2

0 = ln (C)

24 lo g_{10} (2 x) = 60

lo g_{10} (x) = 6.51

What is the answer to log_{4}(x-9)log_{4}(x-9)=7 ?
The answer to log_{4}(x-9)log_{4}(x-9)=7 is x=4^{sqrt(7)}+9,x= 1/(4^{sqrt(7))}+9
Solve for x: log_{4}(x-9)log_{4}(x-9)=7
The solution is x=4^{sqrt(7)}+9,x= 1/(4^{sqrt(7))}+9