What is the answer to 3log_{4}(x+4)-log_{4}(x+4)=2 ?

The answer to 3log_{4}(x+4)-log_{4}(x+4)=2 is x=0

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3log_{4}(x+4)-log_{4}(x+4)=2

3 lo g_{4} (x + 4) - lo g_{4} (x + 4) = 2

x = 0

Solution steps

3 lo g_{4} (x + 4) - lo g_{4} (x + 4) = 2

Add similar elements:

3 lo g_{4} (x + 4) - lo g_{4} (x + 4) = 2 lo g_{4} (x + 4)

2 lo g_{4} (x + 4) = 2

Divide both sides by

2

lo g_{4} (x + 4) = 1

Apply log rules

x + 4 = 4

Solve

x + 4 = 4 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

- ln (x^{5}) = - 5 ln (x)

ln (3 x + 3) = ln (5 x - 9)

ln (7 x + 8) = 2

lo g_{a} (\frac{1}{81}) = - 4

2 = lo g_{10} (\frac{s}{s})

What is the answer to 3log_{4}(x+4)-log_{4}(x+4)=2 ?
The answer to 3log_{4}(x+4)-log_{4}(x+4)=2 is x=0
Solve for x: 3log_{4}(x+4)-log_{4}(x+4)=2
The solution is x=0