What is the answer to 6-4.79=5log_{10}(d-5) ?

The answer to 6-4.79=5log_{10}(d-5) is d=10^{0.242}+5

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6-4.79=5log_{10}(d-5)

6 - 4.79 = 5 lo g_{10} (d - 5)

d = 1 0^{0.242} + 5

Decimal Notation

d = 6.74582 \dots

Solution steps

6 - 4.79 = 5 lo g_{10} (d - 5)

Switch sides

5 lo g_{10} (d - 5) = 6 - 4.79

Subtract the numbers:

6 - 4.79 = 1.21

5 lo g_{10} (d - 5) = 1.21

Divide both sides by

5

lo g_{10} (d - 5) = 0.242

Apply log rules

d - 5 = 1 0^{0.242}

Solve

d - 5 = 1 0^{0.242} : d = 1 0^{0.242} + 5

d = 1 0^{0.242} + 5

Verify Solutions:

d = 1 0^{0.242} + 5

True

The solution is

d = 1 0^{0.242} + 5

lo g_{2} (x^{2} + 5 x + 7) = 0

lo g_{5} (p) = 1.5

ln (2 x + 1) + ln (- x + 1) = 0

lo g_{2} (x - 2) = 2 - lo g_{2} (x + 1)

x, ln (x) = ln (v) + c b

What is the answer to 6-4.79=5log_{10}(d-5) ?
The answer to 6-4.79=5log_{10}(d-5) is d=10^{0.242}+5
Solve for d: 6-4.79=5log_{10}(d-5)
The solution is d=10^{0.242}+5