What is the answer to log_{10}(3)+log_{10}(1-3X)=0 ?

The answer to log_{10}(3)+log_{10}(1-3X)=0 is X= 2/9

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log_{10}(3)+log_{10}(1-3X)=0

lo g_{10} (3) + lo g_{10} (1 - 3 X) = 0

X = \frac{2}{9}

Decimal Notation

X = 0.22222 \dots

Solution steps

lo g_{10} (3) + lo g_{10} (1 - 3 X) = 0

Move

lo g_{10} (3)

to the right side

lo g_{10} (1 - 3 X) = - lo g_{10} (3)

Apply log rules

1 - 3 X = \frac{1}{3}

Solve

1 - 3 X = \frac{1}{3} : X = \frac{2}{9}

X = \frac{2}{9}

Verify Solutions:

X = \frac{2}{9}

True

The solution is

X = \frac{2}{9}

ln (- 4 w - 3) = \frac{1}{2}

2 \cdot lo g_{4} (x) = - 4

lo g_{6} (2 x - 3) = \frac{1}{2}

ln ((x - 9)^{4}) = 12

7.5 = 6 + lo g_{10} (x)

What is the answer to log_{10}(3)+log_{10}(1-3X)=0 ?
The answer to log_{10}(3)+log_{10}(1-3X)=0 is X= 2/9
Solve for X: log_{10}(3)+log_{10}(1-3X)=0
The solution is X= 2/9