What is the answer to log_{3}(sqrt(-7x+1))-7=-4 ?

The answer to log_{3}(sqrt(-7x+1))-7=-4 is x=-104

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log_{3}(sqrt(-7x+1))-7=-4

lo g_{3} (- 7 x + 1) - 7 = - 4

x = - 104

Solution steps

lo g_{3} (- 7 x + 1) - 7 = - 4

Move

7

to the right side

lo g_{3} (- 7 x + 1) = 3

Apply log rules

- 7 x + 1 = 27

Solve

- 7 x + 1 = 27 : x = - 104

x = - 104

Verify Solutions:

x = - 104

True

The solution is

x = - 104

lo g_{3} (32) = 5 lo g_{3} (x)

6 lo g_{49} (r) = 3

y, ln (y - 32) = 5 t

lo g_{9} (8 y - 3) = lo g_{9} (37)

(ln (x)) = 1

What is the answer to log_{3}(sqrt(-7x+1))-7=-4 ?
The answer to log_{3}(sqrt(-7x+1))-7=-4 is x=-104
Solve for x: log_{3}(sqrt(-7x+1))-7=-4
The solution is x=-104