What is the answer to log_{6}(2x-7)=4 ?

The answer to log_{6}(2x-7)=4 is x= 1303/2

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log_{6}(2x-7)=4

lo g_{6} (2 x - 7) = 4

x = \frac{1303}{2}

Decimal Notation

x = 651.5

Solution steps

lo g_{6} (2 x - 7) = 4

Apply log rules

2 x - 7 = 1296

Solve

2 x - 7 = 1296 : x = \frac{1303}{2}

x = \frac{1303}{2}

\frac{k ( x )}{x} + k (x) ln (x) = 0

5 lo g_{10} (x) = 12

e^{3 l n (x)} = x

ln (x) = \frac{1060}{x} + 5.08

ln (x - 3) = 10

What is the answer to log_{6}(2x-7)=4 ?
The answer to log_{6}(2x-7)=4 is x= 1303/2
Solve for x: log_{6}(2x-7)=4
The solution is x= 1303/2