What is the answer to 4-log_{10}(x^2-x+4)=3 ?

The answer to 4-log_{10}(x^2-x+4)=3 is x=3,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4-log_{10}(x^2-x+4)=3

4 - lo g_{10} (x^{2} - x + 4) = 3

x = 3, x = - 2

Solution steps

4 - lo g_{10} (x^{2} - x + 4) = 3

Move

4

to the right side

- lo g_{10} (x^{2} - x + 4) = - 1

Divide both sides by

- 1

lo g_{10} (x^{2} - x + 4) = 1

Apply log rules

x^{2} - x + 4 = 10

Solve

x^{2} - x + 4 = 10 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

True

The solutions are

x = 3, x = - 2

ln (\frac{( x - 2 )}{8}) = 2

2 lo g_{10} (x + 5) + lo g_{3} (9) = 2

3 lo g_{4} (6 x) = 9

5 ln (x) = - 15

lo g_{x} (\frac{19}{65}) = 1.7

What is the answer to 4-log_{10}(x^2-x+4)=3 ?
The answer to 4-log_{10}(x^2-x+4)=3 is x=3,x=-2
Solve for x: 4-log_{10}(x^2-x+4)=3
The solution is x=3,x=-2