What is the answer to 2log_{12}(x-3)+log_{12}(4)=2 ?

The answer to 2log_{12}(x-3)+log_{12}(4)=2 is x=(2sqrt(3))^{2-2log_{12}(2)}+3

Solve for x: 2log_{12}(x-3)+log_{12}(4)=2

The solution is x=(2sqrt(3))^{2-2log_{12}(2)}+3

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2 lo g_{12} (x - 3) + lo g_{12} (4) = 2

x = (23)^{2 - 2 l o g_{12} (2)} + 3

Decimal Notation

x = 9

Solution steps

2 lo g_{12} (x - 3) + lo g_{12} (4) = 2

Move

lo g_{12} (4)

to the right side

2 lo g_{12} (x - 3) = 2 - lo g_{12} (4)

Divide both sides by

2

lo g_{12} (x - 3) = \frac{2 - lo g _{12} ( 4 )}{2}

Apply log rules

x - 3 = (23)^{2 - 2 l o g_{12} (2)}

Solve

x - 3 = (23)^{2 - 2 l o g_{12} (2)} : x = (23)^{2 - 2 l o g_{12} (2)} + 3

x = (23)^{2 - 2 l o g_{12} (2)} + 3

Verify Solutions:

x = (23)^{2 - 2 l o g_{12} (2)} + 3

True

The solution is

x = (23)^{2 - 2 l o g_{12} (2)} + 3

lo g_{10} (x) = 3.931

4 ln (7 x + 2) - 7 = - 15

4.35 = 7 - lo g_{10} (x)

ln (1 - x) = 2

ln (x - 3) = - 1

What is the answer to 2log_{12}(x-3)+log_{12}(4)=2 ?
The answer to 2log_{12}(x-3)+log_{12}(4)=2 is x=(2sqrt(3))^{2-2log_{12}(2)}+3
Solve for x: 2log_{12}(x-3)+log_{12}(4)=2
The solution is x=(2sqrt(3))^{2-2log_{12}(2)}+3