What is the answer to solvefor x,y-8=log_{2}(x+2) ?

The answer to solvefor x,y-8=log_{2}(x+2) is x=2^{y-8}-2

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solvefor x,y-8=log_{2}(x+2)

solve for

x, y - 8 = lo g_{2} (x + 2)

x = 2^{y - 8} - 2

Solution steps

y - 8 = lo g_{2} (x + 2)

Apply log rules

2^{y - 8} = x + 2

Solve

2^{y - 8} = x + 2 : x = 2^{y - 8} - 2

x = 2^{y - 8} - 2

lo g_{3 - x} (x^{2} + x) = 1

1 - 2 lo g_{10} (x) = - 4

lo g_{2} (5 x - 2) = 3 + lo g_{2} (3 x)

lo g_{2} (4 x + 5) = lo g_{2} (2 x + 11)

5 lo g_{5} (2) = lo g_{5} (x)

What is the answer to solvefor x,y-8=log_{2}(x+2) ?
The answer to solvefor x,y-8=log_{2}(x+2) is x=2^{y-8}-2