What is the answer to log_{10}(x^2+13x-5)=0 ?

The answer to log_{10}(x^2+13x-5)=0 is x=(-13+sqrt(193))/2 ,x=(-13-sqrt(193))/2

Solve for x: log_{10}(x^2+13x-5)=0

The solution is x=(-13+sqrt(193))/2 ,x=(-13-sqrt(193))/2

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lo g_{10} (x^{2} + 13 x - 5) = 0

x = \frac{- 13 + 193}{2}, x = \frac{- 13 - 193}{2}

Decimal Notation

x = 0.44622 \dots, x = - 13.44622 \dots

Solution steps

lo g_{10} (x^{2} + 13 x - 5) = 0

Apply log rules

x^{2} + 13 x - 5 = 1

Solve

x^{2} + 13 x - 5 = 1 : x = \frac{- 13 + 193}{2}, x = \frac{- 13 - 193}{2}

x = \frac{- 13 + 193}{2}, x = \frac{- 13 - 193}{2}

lo g_{4} (x) = 0.5

ln (x^{2}) - (ln (x))^{2} = 0

lo g_{X} (\frac{2}{3}) = 4

lo g_{x} (3 - 1) = - 1

lo g_{3} (6 x + 34) = lo g_{3} (- 2)

What is the answer to log_{10}(x^2+13x-5)=0 ?
The answer to log_{10}(x^2+13x-5)=0 is x=(-13+sqrt(193))/2 ,x=(-13-sqrt(193))/2
Solve for x: log_{10}(x^2+13x-5)=0
The solution is x=(-13+sqrt(193))/2 ,x=(-13-sqrt(193))/2