What are the solutions to the equation -8x^2+7x+6=2 ?

The solutions to the equation -8x^2+7x+6=2 are x=-(-7+sqrt(177))/(16),x=(7+sqrt(177))/(16)

Find the zeros of -8x^2+7x+6=2

The zeros of -8x^2+7x+6=2 are x=-(-7+sqrt(177))/(16),x=(7+sqrt(177))/(16)

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- 8 x^{2} + 7 x + 6 = 2

x = - \frac{- 7 + 177}{16}, x = \frac{7 + 177}{16}

Decimal Notation

x = - 0.39400 \dots, x = 1.26900 \dots

Solution steps

- 8 x^{2} + 7 x + 6 = 2

Move

2

to the left side

- 8 x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 8 ) \cdot 4}{2 ( - 8 )}

7^{2} - 4 (- 8) \cdot 4 = 177

x_{1, 2} = \frac{- 7 \pm 177}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 7 + 177}{2 ( - 8 )}, x_{2} = \frac{- 7 - 177}{2 ( - 8 )}

x = \frac{- 7 + 177}{2 ( - 8 )} : - \frac{- 7 + 177}{16}

x = \frac{- 7 - 177}{2 ( - 8 )} : \frac{7 + 177}{16}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 177}{16}, x = \frac{7 + 177}{16}

2.2 n = - 13.8 + 1.2 n

5 x + \frac{1}{2} - 2 < 5

\frac{- 14}{- 2}

\frac{1}{6} + \frac{1}{18}

\frac{( x + 2 )}{( x + 1 )}

What are the solutions to the equation -8x^2+7x+6=2 ?
The solutions to the equation -8x^2+7x+6=2 are x=-(-7+sqrt(177))/(16),x=(7+sqrt(177))/(16)
Find the zeros of -8x^2+7x+6=2
The zeros of -8x^2+7x+6=2 are x=-(-7+sqrt(177))/(16),x=(7+sqrt(177))/(16)