What is the answer to ln(x+1/2)=ln(2x+1) ?

The answer to ln(x+1/2)=ln(2x+1) is No Solution for x\in\mathbb{R}

Solve for x: ln(x+1/2)=ln(2x+1)

The solution is No Solution for x\in\mathbb{R}

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ln (x + \frac{1}{2}) = ln (2 x + 1)

No Solution for x \in R

Solution steps

ln (x + \frac{1}{2}) = ln (2 x + 1)

Apply log rules

x + \frac{1}{2} = 2 x + 1

Solve

x + \frac{1}{2} = 2 x + 1 : x = - \frac{1}{2}

x = - \frac{1}{2}

Verify Solutions:

x = - \frac{1}{2}

False

The solution is

No Solution for x \in R

- 35 = 10 lo g_{10} (\frac{x}{1})

lo g_{10} (lo g_{10} (x)) = 4

lo g_{x} (3) = lo g_{3} (9 x)^{3}

\frac{1}{e ^{0.243}} = ln (x)

lo g_{10} (P) = 4.4366

What is the answer to ln(x+1/2)=ln(2x+1) ?
The answer to ln(x+1/2)=ln(2x+1) is No Solution for x\in\mathbb{R}
Solve for x: ln(x+1/2)=ln(2x+1)
The solution is No Solution for x\in\mathbb{R}