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Popular >

solvefor y,ln(y)=-kt+c

Solution

solve for

y, ln (y) = - k t + c

Solution

y = e^{- k t + c}

Solution steps

ln (y) = - k t + c

Apply log rules

y = e^{- k t + c}

Popular Examples

log_{10}(X)=-4.2

lo g_{10} (X) = - 4.2

15=log_{1.02}(9x+1)

15 = lo g_{1.02} (9 x + 1)

log_{2/3}(4x-2)=3

lo g_{\frac{2}{3}} (4 x - 2) = 3

- 1 - 5 \cdot ln (x) = 1.2

solvefor P,ln(P)=a-b(ln(Q))solve for

P, ln (P) = a - b (ln (Q))

Frequently Asked Questions (FAQ)

What is the answer to solvefor y,ln(y)=-kt+c ?
The answer to solvefor y,ln(y)=-kt+c is y=e^{-kt+c}