What is the answer to log_{4}(x)+log_{2}(x+2)=3 ?

The answer to log_{4}(x)+log_{2}(x+2)=3 is x\approx 2.78971…

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log_{4}(x)+log_{2}(x+2)=3

lo g_{4} (x) + lo g_{2} (x + 2) = 3

x \approx 2.78971 \dots

Solution steps

lo g_{4} (x) + lo g_{2} (x + 2) = 3

Apply log rules

x (x + 2)^{2} = 64

Solve

x (x + 2)^{2} = 64 : x \approx 2.78971 \dots

x \approx 2.78971 \dots

Verify Solutions:

x \approx 2.78971 \dots

True

The solution is

x \approx 2.78971 \dots

1 = ln (1 - x) + ln (x)

lo g_{10} (x) = 0.4104

x = a^{l o g_{a} (x)}

5 = lo g_{10} (\frac{x}{2})

ln (X) = 3.4146

What is the answer to log_{4}(x)+log_{2}(x+2)=3 ?
The answer to log_{4}(x)+log_{2}(x+2)=3 is x\approx 2.78971…
Solve for x: log_{4}(x)+log_{2}(x+2)=3
The solution is x\approx 2.78971…