What is the answer to -log_{10}(x)=10^{-2} ?

The answer to -log_{10}(x)=10^{-2} is x= 1/(\sqrt[100]{10)}

Solve for x: -log_{10}(x)=10^{-2}

The solution is x= 1/(\sqrt[100]{10)}

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- lo g_{10} (x) = 1 0^{- 2}

Decimal Notation

x = 0.97723 \dots

Solution steps

- lo g_{10} (x) = 1 0^{- 2}

Simplify

1 0^{- 2} : \frac{1}{100}

- lo g_{10} (x) = \frac{1}{100}

Divide both sides by

- 1

lo g_{10} (x) = - \frac{1}{100}

Apply log rules

Verify Solutions:

True

The solution is

lo g_{4} (x) = 1.7

lo g_{1296} (x) = - \frac{3}{4}

3^{l o g_{10} (2 y - x)} = 1

100 = lo g_{5} (x)

ln (x + 1) = 9

What is the answer to -log_{10}(x)=10^{-2} ?
The answer to -log_{10}(x)=10^{-2} is x= 1/(\sqrt[100]{10)}
Solve for x: -log_{10}(x)=10^{-2}
The solution is x= 1/(\sqrt[100]{10)}