What is the answer to e^{ln(x+C)} 1/(x+C)=1 ?

The answer to e^{ln(x+C)} 1/(x+C)=1 is True for all x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^{ln(x+C)} 1/(x+C)=1

e^{l n (x + C)} \frac{1}{x + C} = 1

True for all x

Solution steps

e^{l n (x + C)} \frac{1}{x + C} = 1

Multiply both sides by

x + C

e^{l n (x + C)} = x + C

Apply log rules

x + C = x + C

Both sides are equal

True for all x

x, lo g_{6} (5 - 4 x) = 3

ln (x + 1) = x

ln (x + 1) = a

y, ln (y^{2}) = x + 1

5.7 = - lo g_{10} (x)

What is the answer to e^{ln(x+C)} 1/(x+C)=1 ?
The answer to e^{ln(x+C)} 1/(x+C)=1 is True for all x