What is the answer to solvefor y,2ln(y)=x^2+c ?

The answer to solvefor y,2ln(y)=x^2+c is y=e^{(x^2+c)/2}

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solvefor y,2ln(y)=x^2+c

solve for

y, 2 ln (y) = x^{2} + c

y = e^{\frac{x ^{2} + c}{2}}

Solution steps

2 ln (y) = x^{2} + c

Divide both sides by

2

ln (y) = \frac{x ^{2} + c}{2}

Apply log rules

y = e^{\frac{x ^{2} + c}{2}}

lo g_{10} (x) = - 2.6

x, - ln (x) = y

x^{2} - 6 x ln (x) = 0

lo g_{10} (22.46) = lo g_{10} (x)

3 lo g_{4} (x) = lo g_{4} (343)

What is the answer to solvefor y,2ln(y)=x^2+c ?
The answer to solvefor y,2ln(y)=x^2+c is y=e^{(x^2+c)/2}