What is the answer to 6log_{8}(3x+1)=log_{8}(64) ?

The answer to 6log_{8}(3x+1)=log_{8}(64) is x= 1/3

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6log_{8}(3x+1)=log_{8}(64)

6 lo g_{8} (3 x + 1) = lo g_{8} (64)

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

6 lo g_{8} (3 x + 1) = lo g_{8} (64)

Divide both sides by

6

lo g_{8} (3 x + 1) = \frac{lo g _{8} ( 64 )}{6}

Apply log rules

3 x + 1 = 2

Solve

3 x + 1 = 2 : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

x = lo g_{3} (x)

(x) 6 - 5 ln (x) = 2

ln (\frac{1}{x}) = 1.147629

lo g_{3} (x) - lo g_{3} (x + 5) = 1

What is the answer to 6log_{8}(3x+1)=log_{8}(64) ?
The answer to 6log_{8}(3x+1)=log_{8}(64) is x= 1/3
Solve for x: 6log_{8}(3x+1)=log_{8}(64)
The solution is x= 1/3