What is the answer to 20log_{10}(k)=6.02 ?

The answer to 20log_{10}(k)=6.02 is k=10^{0.301}

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20log_{10}(k)=6.02

20 lo g_{10} (k) = 6.02

k = 1 0^{0.301}

Decimal Notation

k = 1.99986 \dots

Solution steps

20 lo g_{10} (k) = 6.02

Divide both sides by

20

lo g_{10} (k) = 0.301

Apply log rules

k = 1 0^{0.301}

Verify Solutions:

k = 1 0^{0.301}

True

The solution is

k = 1 0^{0.301}

lo g_{b} (32) = \frac{5}{6}

lo g_{2} (x) + lo g_{2} (2 x - 3) = 1

2 lo g_{3} (x) - 3 = 0

ln (x - 5) = - 1

lo g_{a} (729) = 3

What is the answer to 20log_{10}(k)=6.02 ?
The answer to 20log_{10}(k)=6.02 is k=10^{0.301}
Solve for k: 20log_{10}(k)=6.02
The solution is k=10^{0.301}