What is the answer to 6*ln(3x+4)-7=5 ?

The answer to 6*ln(3x+4)-7=5 is x=(e^2-4)/3

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6*ln(3x+4)-7=5

6 \cdot ln (3 x + 4) - 7 = 5

x = \frac{e ^{2} - 4}{3}

Decimal Notation

x = 1.12968 \dots

Solution steps

6 ln (3 x + 4) - 7 = 5

Move

7

to the right side

6 ln (3 x + 4) = 12

Divide both sides by

6

ln (3 x + 4) = 2

Apply log rules

3 x + 4 = e^{2}

Solve

3 x + 4 = e^{2} : x = \frac{e ^{2} - 4}{3}

x = \frac{e ^{2} - 4}{3}

Verify Solutions:

x = \frac{e ^{2} - 4}{3}

True

The solution is

x = \frac{e ^{2} - 4}{3}

ln (- 7 r - 3) = ln (- 3 r + 5)

ln (y) = ln (4) + 5

lo g_{5} (3 x + 19) = 4

lo g_{81} (2 r - 1) = \frac{- 1}{2}

x, ln (x) - ln (x^{2}) = 5

What is the answer to 6*ln(3x+4)-7=5 ?
The answer to 6*ln(3x+4)-7=5 is x=(e^2-4)/3
Solve for x: 6*ln(3x+4)-7=5
The solution is x=(e^2-4)/3