What is the answer to x 1/240 =ln(x) ?

The answer to x 1/240 =ln(x) is x=-240\W_{-1}(-1/240),x=-240\W_{0}(-1/240)

Solve for x: x 1/240 =ln(x)

The solution is x=-240\W_{-1}(-1/240),x=-240\W_{0}(-1/240)

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x \frac{1}{240} = ln (x)

x = - 240 W_{- 1} (- \frac{1}{240}), x = - 240 W_{0} (- \frac{1}{240})

Decimal Notation

x = 1798.76539 \dots, x = 1.00419 \dots

Solution steps

x \frac{1}{240} = ln (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{x \frac{1}{240}} = e^{l n (x)}

Simplify

e^{l n (x)} : x

e^{x \frac{1}{240}} = x

Solve

e^{x \frac{1}{240}} = x : x = - 240 W_{- 1} (- \frac{1}{240}), x = - 240 W_{0} (- \frac{1}{240})

x = - 240 W_{- 1} (- \frac{1}{240}), x = - 240 W_{0} (- \frac{1}{240})

Verify Solutions:

x = - 240 W_{- 1} (- \frac{1}{240})

True

, x = - 240 W_{0} (- \frac{1}{240})

True

The solutions are

x = - 240 W_{- 1} (- \frac{1}{240}), x = - 240 W_{0} (- \frac{1}{240})

ln^{(2)} (x^{(3)}) = e

e^{- 2 l n (x)} = - 2 x

lo g_{6} (7 x) = 4

ln (x - 2) = i n^{12} - in (x + 2)

lo g_{3} ((x + 1) (x + 3)) = 1

What is the answer to x 1/240 =ln(x) ?
The answer to x 1/240 =ln(x) is x=-240\W_{-1}(-1/240),x=-240\W_{0}(-1/240)
Solve for x: x 1/240 =ln(x)
The solution is x=-240\W_{-1}(-1/240),x=-240\W_{0}(-1/240)